Math, asked by venkateshbhavikatti1, 4 months ago

cos^A + sin^ = 1 , how?​

Answers

Answered by sakshamnirala1p434vq
0

Step-by-step explanation:

Explanation:

Assuming you mistyped and meant

sin

1

(

cos

(

x

)

)

or simply

arcsin

(

cos

(

x

)

)

, we can easily solve this by putting it on terms of the sine function.

We know that the cosine function, is nothing more than the sine

π

2

radians out of phase, as proved below:

cos

(

θ

π

2

)

=

cos

(

θ

)

cos

(

π

2

)

sin

(

θ

)

sin

(

π

2

)

cos

(

θ

π

2

)

=

cos

(

θ

)

0

(

sin

(

θ

)

sin

(

π

2

)

)

cos

(

θ

π

2

)

=

sin

(

θ

)

1

=

sin

(

θ

)

So we can say that the sine function, 90 degrees ahead, is the cosine function.

arcsin

(

cos

(

x

)

)

=

arcsin

(

sin

(

x

+

π

2

)

)

Using the property of inverse functions that

f

1

(

f

(

x

)

)

=

x

, we have

arcsin

(

cos

(

x

)

)

=

x

+

π

2

If you must use degrees, just convert those

π

2

radians to

90

º

degrees.

Answered by rinasingh9006555970
3

Answer:

Cos^ + sin^ = 1

Step-by-step explanation:

Sin theta =b/c (opposite side /hypotenuse)

Cos theta =a/c (adjacent side /hypotenuse)

Sin ^theta +cos ^theta = b^/c^ +a^/c^ =a^+b^/c^

By pythagoras theorem

C^=a^+b^

. : cos ^+ sin ^=1

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