cos A + sin (270° + A) - sin (270° - A)
+ cos (180° + A) =
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Answered by
2
Answer:
from 233AB is the answer
Answered by
6
Answer:
Step-by-step explanation:
in (270+A) =-cos A cos (180+A)= -cosA
sin (270-A) =-cos A
therefore left hand side,
sin (270+A) +cosA + cos (180+A) - sin(270-A)
= -cosA + cosA - cosA + cosA
= 0
hence proved
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