cos A+sin^2AsecA=secA
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Answered by
1
Answer:
11-Sep-2016 · 2 answers
Lhs = cos 2A/secA+sin2A/ cosecA = cos2A cosA+sin 2A sinA ( since 1/ secA = cosA, 1/cosec A = sinA) = cos(2A-A)
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Answered by
2
Answer:
cosA +sin^2 A sec A = SecA
LHS :-cos^2A + sin ^A / cosA
1/cosA
= secA
RHS
Step-by-step explanation:
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