Math, asked by prajwal02, 10 months ago

cos a+sin a/cos a-sin a -cos a- sin a/cos a+ sin a= 2tan 2a​

Answers

Answered by aadi7571
35

LHS

(cosa + sina)/(cosa - sina) - (cosa - sina)/(cosa + sina)

= ((cosa + sina)^2 - (cosa - sina)^2) / (cosa + sina)(cosa - sina)

= (cosa + sina + cosa - sina)(cosa + sina - cosa + sina) / (cos^2a - sin^2a)

= 2cosa*2sina/(cos^2a - sin^2a)

(2*sina*cosa = sin2a and cos^2a - sin^2a = cos2a)

= 2sin2a/cos2a = 2*tan2a = RHS    Ans...

Answered by legendarygamer009
0

explanation in the snap attached to this answer.

Attachments:
Similar questions