Question

cos A +sin B =1;A=60°and B is an acute angle , then find the value of B​

Answer 1

Answer:

Hence B is equal to 30 degrees.

Step-by-step explanation:

$cosA+sinB=1$

$cos60+sinB=1$

$\frac{1}{2} +sinB=1$

$sinB=1-\frac{1}{2}$

$sinB=\frac{2-1}{2}$

$sinB=\frac{1}{2}$

$sinB=sin30$

$B=30$

Answer 2

Answer:

cosA+sinB =1 (given)

putting the vale of A=60

cos 60+sinA=sin90 (sin 1= sin 90)

then

cos(90-60)+sinB=sin90

on equating sin we get

sin 60+ B = 90

60+B=90

B=90-60

.

. . B=30

Step-by-step explanation: