Cos a + Sin b = 2, find a+b.
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if sin (a-b) =sinACos B-CosAsinB and Cos(a-b)=CosACosBsinB
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Heya guys...
I think in ur question there r some mistaken done by u...
But I'll give u a such example then u can understand by this
That is question
if sin a + sin b=2 , then find the value of sin (a+b).
And solution is.....
There is only 1 possibility for sin A +sin B to be equal to 2.
max value of sinθ is 1...
so sin A = 1 and sin B = 1.....
therefore A = B = 90°
sin (A+B) = sin (90°+90°) = sin 180°= 0
Hopes it will help u
Thanks
I think in ur question there r some mistaken done by u...
But I'll give u a such example then u can understand by this
That is question
if sin a + sin b=2 , then find the value of sin (a+b).
And solution is.....
There is only 1 possibility for sin A +sin B to be equal to 2.
max value of sinθ is 1...
so sin A = 1 and sin B = 1.....
therefore A = B = 90°
sin (A+B) = sin (90°+90°) = sin 180°= 0
Hopes it will help u
Thanks
abhijaydutta123:
But cos 0° =< 1 amd sin 90° = 1 then......
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