cos A _ sinA +1 /cosA + sinA_1 =cosec A + cos^A
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Hai bro this is your answer
cosA-sinA+1/cosA+sinA-1=cosecA+cosA?
LHS=
cosA(cosA-sinA+1)/cosA(cosA+sinA-1)
=> cosA(cosA-sinA+1)/cos²A+sinAcosA-cosA
=> cosA(cosA-sinA+1)/1-sin²A+sinAcosA-cosA
=> cosA(cosA-sinA+1)/(1-sinA) (1+sinA)-cosA(1- sinA)
=> cosA(cosA-sinA+1)/(1+sinA)(1-sinA+cosA)
=> cosA/1+sinA
=> cosA/1 + 1/sinA
=> cosA+cosecA
LHS=RHS
Hense prove. _________###swarnim ##
I hope this is helpful for you
cosA-sinA+1/cosA+sinA-1=cosecA+cosA?
LHS=
cosA(cosA-sinA+1)/cosA(cosA+sinA-1)
=> cosA(cosA-sinA+1)/cos²A+sinAcosA-cosA
=> cosA(cosA-sinA+1)/1-sin²A+sinAcosA-cosA
=> cosA(cosA-sinA+1)/(1-sinA) (1+sinA)-cosA(1- sinA)
=> cosA(cosA-sinA+1)/(1+sinA)(1-sinA+cosA)
=> cosA/1+sinA
=> cosA/1 + 1/sinA
=> cosA+cosecA
LHS=RHS
Hense prove. _________###swarnim ##
I hope this is helpful for you
Anonymous:
thanks
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