cos A + SinA =√2 cosA ; then cosA -sinA=?
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Answered by
3
Given
→ cosA + sinA = √2 cosA
Then squaring both sides we get,
→ cos²A + sin²A + 2 cosA sinA = 2 cos²A
→ 1 + 2cosA sinA = 2 cos²A
→ 2 cosA sinA = 2 cos²A - 1
Then,
→ (cosA - sinA)² = cos²A + sin²A - 2 cosA sinA
→ (cosA - sinA)² = cos²A + sin²A - (2cos²A - 1)
→ (cosA - sinA)² = 1 - 2cos²A + 1
→ cosA - sinA = √(2 - 2cos²A)
Answer: √(2 - 2cos²A)
Answered by
1
Answer:
Step-by-step explanation:
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