Math, asked by arb26, 4 months ago

cos^A+tan^A-1/sin^A=tan^A

Answers

Answered by shinchan4448

3

Step-by-step explanation:

L.H.S. =

1+sinA

cosA

+tanA

=

1+sinA

cosA

+

cosA

sinA

=

(1+sinA)cosA

cos

2

A+sinA(1+sinA)

=

(1+sinA)(cosA)

cos

2

A+sinA+sin

2

A

=

(1+sinA)cosA

1+sinA

=

cosA

1

=secA= R.H.S.

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