Question

cos alfa . sin (bita – gema) + cos bita . sin (gema - alfa ) + cos gema . sin (alfa - bita )​

Answer 1

Answer:

given,

z=αsinθ+βcosθ

z=

α

2

+β

2

[

α

2

+β

2

α

sinθ+

α

2

+β

2

β

cosθ]

let,

cosϕ=

α

2

+β

2

α

⇒sinϕ=

1−cos

2

ϕ

=

1−

α

2

+β

2

α

2

=

α

2

+β

2

β

z=

α

2

+β

2

[cosϕsinθ+sinϕcosθ]

z=

α

2

+β

2

sin(ϕ+θ)

−1≤sin(ϕ+θ)≤1

−

α

2

+β

2

≤

α

2

+β

2

sin(ϕ+θ)≤

α

2

+β

2

−

α

2

+β

2

≤z≤

α

2

+β

2