Math, asked by avanimishra8989, 1 year ago

Cos(alpha+beta)=a^2-b^2÷a^2+b^2

Answers

Answered by singhsujal6465
0

 { \sqrt[ | - .93 | { \div  - .}^{?} | | ]{?} }^{?}  { {x}^{2} }^{2}
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