Cos alpha+ cos 3alpha +cos 5alpha+ cos 7alpha+ cos 9alpha =sin 10alpha/2sin alpha
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Answer:
Correct option is
C
1
cos9α=sinα
⇒cos9α=cos(90°−α)
⇒9α=90°−α
⇒10α=90°
⇒α=9°
∴tan5α=tan45°=1
Hence, the answer is 1.
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