cos e Solve the equation : cos e + 1+sin
0 = 4 1-sin 0
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Answer:
(1+sin
2
θ)=3sinθcosθ
⇒2+2sin
2
θ=3×2sinθcosθ
⇒2+1−cos2θ=3sin2θ
⇒3−cos2θ=3sin2θ
⇒3−
1+tan
2
θ
1−tan
2
θ
=3×
1+tan
2
θ
2tanθ
⇒
1+tan
2
θ
3+3tan
2
θ+1−tan
2
θ
=
1+tan
2
θ
6tanθ
⇒3+3tan
2
θ+1−tan
2
θ=6tanθ
⇒4+2tan
2
θ−6tanθ=0
⇒2tan
2
θ−6tanθ+4=0
⇒tan
2
θ−3tanθ+2=0
⇒(tanθ−1)(2tanθ−1)=0
⇒tanθ=1 or
2
1
Hence the given statement is false.
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