( CosӨ + i SinӨ) whole square is equal to .
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CosӨ + i SinӨ) whole square is
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Step-by-step explanation:
(a+b)² =a²+b²+2ab=
(cos theta+sin theta)²=cos²theta+sin²theta+2× costheta×sintheta
=by trigonometric identity which is sin²theta+cos²theta=1
by substituting in the equation (sin²theta+cos²theta) we get
1
therefore 1×2sin theta cos theta
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