cos(pi/2 + theta) = -sin theta
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Step-by-step explanation:
let theta = ∝
cos(pi/2 + theta) = -sin theta
cos(π2 + ∝) = -sin ∝
cos (π/2 - ∝) = -sin ∝
sin∝ = - sin∝
sin∝ = 0
∝ = 0 , ±π , ±2π , ... = nπ , nis integer
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