cos(piee/4-thta)cos(piee/4-fiee) -(piee/4-thta)sin (piee/4-fiee) show that sin (thta+fiee)
Answers
Answer:
Step-by-step explanation:Let angle theta be represented by A.
(sinA + Sec A)² + (cos A + cosec A)²
= [ (SinA CosA + 1)²/CosA ]² + [ (CosA SinA + 1)² / Sin²A ]
= (1+ SinA CosA)² * [1 / Cos²A + 1/sin²A ]
= (1 + SinA CosA)² * [ Cos²A + Sin²A]/ [cos²A * Sin²A ]
= ( 1 + SinA CosA)²/ (cosA * SinA)²
= [ 1/cosA * 1/sinA + 1 ] ²
= [ Sec A Cosec A + 1 ]²
Let angle theta be represented by A.
Step-by-step explanation:
Let pi /4 - tan theta be represented by A.
(sinA + Sec A)² + (cos A + cosec A)²
= [ (SinA CosA + 1)²/CosA ]² + [ (CosA SinA + 1)² / Sin²A ]
= (1+ SinA CosA)² * [1 / Cos²A + 1/sin²A ]
= (1 + SinA CosA)² * [ Cos²A + Sin²A]/ [cos²A * Sin²A ]
= ( 1 + SinA CosA)²/ (cosA * SinA)²
= [ 1/cosA * 1/sinA + 1 ] ²
= [ Sec A Cosec A + 1 ]²
Put value A to get reqd