Question

cos/sec-tan = 1+sin
Plz prove it​

Answer 1

$\frac{cos}{sec - tan} \\ = \frac{cos}{ \frac{1 - sin}{cos} } \\ = \frac{ {cos}^{2} }{1 - sin} \\ = \frac{1 - {sin}^{2} }{1 - sin} \\ = \frac{(1 - sin)(1 + sin)}{1 - sin} \\ = 1 + sin$