(cos-sin)^2+(cos+sin)^2=1
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Your question needs a little correction, ie, RHS = 2 and not 1.
LHS
= (cosθ - sinθ)² + (cosθ + sinθ)²
= cos²θ + sin²θ - 2cosθsinθ + cos²θ + sin²θ + 2cosθsinθ
We know that sin²θ + cos²θ = 1
So, LHS
= 1 + 1 + 0
= 2
= RHS
Hence, proved.
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