Question

cos-sin/cos+sin=1-√3/1+√3

Answer 1

what is the question..
if angle is meant to be found out...refer to the solution.
hope it helps ☺

Answer 2

The value of ∠A = 60°.

Step-by-step explanation:

We have,

$\dfrac{\cos A-\sin A}{\cos A+\sin A}} =\dfrac{1-\sqrt{3}}{1+\sqrt{3}}$

To find, the value of ∠A = ?

∴ $\dfrac{\cos A-\sin A}{\cos A+\sin A}} =\dfrac{1-\sqrt{3}}{1+\sqrt{3}}$

$= \dfrac{\dfrac{\cos A-\sin A}{\cos A}}{\dfrac{\cos A+\sin A}{\cos A}} =\dfrac{1-\sqrt{3}}{1+\sqrt{3}}$

$= \dfrac{1-\tan A}{1+\tan A}  =\frac{1-\sqrt{3} }{1+\sqrt{3}}$

∴$\tan A=\sqrt{3}$

⇒$\tan A=\tan 60$

⇒ ∠A = 60°

Hence, the value of ∠A = 60°.