Math, asked by manishaparesh84, 9 months ago

cos square 45-cos square 30=x.cos 45. sin 45, x=?

Answers

Answered by tennetiraj86
0

Answer:

answer for the given problem is given

Attachments:
Answered by Unni007
2

\displaystyle\sf{\longrightarrow{cos^2(45)= (\frac{1}{\sqrt2})^2 = \bold{\frac{1}{2}}}

\displaystyle\sf{\longrightarrow{cos^2(30)=(\frac{\sqrt3}{2})^2 = \bold{\frac{3}{4}}

\displaystyle\sf{\longrightarrow{cos(45)=\bold{\frac{1}{\sqrt2}}

\displaystyle\sf{\longrightarrow{sin(45)=\bold{\frac{1}{\sqrt2}}

Given,

\displaystyle\sf{cos^2(45)-cos^2(30)=x\:.\:cos(45)\:.\:sin(45)

\displaystyle\sf{\implies\frac{1}{2}-\frac{3}{4}=x\:.\:\frac{1}{\sqrt2}\:.\:\frac{1}{\sqrt2}

\displaystyle\sf{\implies \frac{-1}{4}=\frac{x}{2}

\displaystyle\sf{\implies x=\frac{-1}{2}

\displaystyle\sf{\boxed{\bold{ x=\frac{-1}{2}}}}

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