Question

cos square theta bracket 1 - cos theta bracket close by sin square theta bracket 1 - sin theta bracket close barabar 1 + sin theta by 1 + cos theta​

Answer 1

Answer:is given below

Step-by-step explanation:

Cos^2(A){1-CosA}/{Sin^2(A)(1-SinA)}=(1+SinA/1+cosA)

RHS=(1+sinA)/(1+cosA)

=(1+sinA)(1-cosA)/(1+CosA)(1-cosA)

=(1+sinA)(1-cosA)/(1-cos^2A)

=(1+sinA)(1-cosA)/(Sin^2A)

=(1+sinA)(1-cosA)(1-SinA)/{Sin^2A(1-SinA)}

=(1-Sin^2A)(1-cosA)/{Sin^2A(1-SinA)}

=Cos^2A(1-cosA)/{Sin^2A(1-SinA)}

=LHS

Answer 2

Answer:

Answer is 1 .

I hope it helps..