Question

Cos square theta + cos square pi by 6 + cos square pi by 3 + cos square pi by 2

Answer 1

$cos^2\theta +cos^2\frac{\pi}{6}+cos^2\frac{\pi}{3}+cos^2\frac{\pi}{2}$

$cos^2\frac{\pi}{6}=\frac{3}{2^2}$

$cos^2\frac{\pi}{3}=\frac{1}{2^2}$

$cos^2\frac{\pi}{2}=0$

$cos^2\theta+\frac{3}{2^2}+\frac{1}{2^2}+0$

Combining the fractions$\frac{3}{2^2} +\frac{1}{2^2} =1$

$cos^2\theta+1+0$

$cos^2\theta+1$

Final Answer: $cos^2\theta+1$