cos square theta into (1 + tan square theta )is equal to 1
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Solution:
Here I am using A instead of theta.
LHS = cos²A (1+tan²A)
= cos²A×sec²A
[ Since ,1+tan²A = sec²A ]
= cos²A × ( 1/cos²A)
[ Since , secA = 1/cosA ]
= 1
= RHS
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