cos square theta upon sin theta-cosec theta+sin theta=0
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hey there is ua solution.....
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Ans: (1-Cos2 A) Cosec2 A = Sin2 A Cosec2 A. = (Sin A ... (Cosec A Sin A)2. = ((1/Sin A) x Sin A )2. = (1)2 = 1. Q3: tan2θcos2θ = 1−cos2θ.
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Ans: (1-Cos2 A) Cosec2 A = Sin2 A Cosec2 A. = (Sin A ... (Cosec A Sin A)2. = ((1/Sin A) x Sin A )2. = (1)2 = 1. Q3: tan2θcos2θ = 1−cos2θ.
syedmdsaif827:
hey
I hope it helps u
we have to prove RHS=0 not understood the solution
ooh
sry
by the way ua name
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