Question

cos teeta - sin teeta / cos teeta + sin teeta =1-√3/1+√3.Find teeta ​

Answer 1

$\displaystyle\frac{\cos\theta - \sin\theta}{\cos\theta + \sin\theta } = \frac{1 - \sqrt{3}}{1 +\sqrt{3}}$

$\displaystyle\frac{\cos\theta - \sin\theta}{\cos\theta + \sin\theta } = \frac{\frac{1 - \sqrt{3}}{2}}{\frac{1 +\sqrt{3}}{2}} = \frac{\frac{1}{2} - \frac{\sqrt{3}}{2}}{\frac{1}{2} + \frac{\sqrt{3}}{2}}$

On  comparing both sides, we get:

$\displaystyle \cos\theta = \frac{1}{2} \text{ and } \sin\theta = \frac{\sqrt{3}}{2}$

$\displaystyle \therefore \theta = 60^{\circ}$