(cos teta + i sin teta)^6 / ( cos teta - I sin teta)^5 = ?
a) cos 11 teta - i sin 11 teta
b) cos 11 teta + i sin 11 teta
c) cos teta + i sin teta
d) cos 6 teta/5 + i sin 6 teta/5
Answers
Answered by
0
Answer:
I think option a is right
Answered by
0
THE ANSWER IS OPTION A
HOPE IT HELPS YOU
Similar questions