Question

cos teta - sec teta equal to 2 then cos n teta + sec n teta​

Answer 1

cosx+1cosx=2

=cos2x+1=2cosx

=cos2x−2cosx+1=0

=(cosx−1)2=0

=cosx=1

=secx=1

∴ (cosx)^100 + (secx)^100 = 2

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