cos theeta ÷1+sin theeta
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I hope this is correct and if it helped you please mark it brainliest
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cosA / ( 1 + sinA )
Multiply and divide by 1 - sinA
cosA( 1 - sinA ) / ( 1 + sinA )( 1 - sinA )
cosA( 1 - sinA ) / 1 - sin²A
cosA( 1 - sinA ) / cos²A
( 1 - sinA ) / cosA
Multiply and divide by 1 - sinA
cosA( 1 - sinA ) / ( 1 + sinA )( 1 - sinA )
cosA( 1 - sinA ) / 1 - sin²A
cosA( 1 - sinA ) / cos²A
( 1 - sinA ) / cosA
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