cos theeta-sin theeta /cos theeta+sin theeta=1-√3/1+√3a.
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Step-by-step explanation:
Answer
cosθ+sinθ
cosθ−sinθ
=
1+
3
1−
3
cosθ
cosθ+sinθ
cosθ
cosθ−sinθ
=
1+
3
1−
3
1+tanθ
1−tanθ
=
1+
3
1−
3
On comparing the two sides, we get,
tanθ=
3
=tan60
o
θ=60
o
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