Question

cos theta = 0.6 and theta is not in the first quadrant then 5sin theta - 3tan theta / 3sec theta - 4cot theta =​

Answer 1

Answer:

a/q angle should be in 4th quadrant.

$cos \alpha = 0.6$

then

$sin \alpha = - \sqrt{1 - {0.6}^{2} } = - 0.8 = - \frac{4}{5}$

$tan \alpha = - \frac{0.8}{0.6} = - \frac{4}{3}$

$cot \alpha = - \frac{3}{4}$

$sec \alpha = \frac{1}{0.6} = \frac{5}{3}$

find these values in question, you will get answer.