cos theta=1/√3 to tan+sec theta=?
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Hii
you are welcome in my ans
cos@ = 1/sqrt3
sec@ = sqrt3
on squiring both side
sec^2@ = 3
sec^2@ = 1+ tan^2@
tan@ = sqrt2
so
tan@ + sec@ = sqrt3 + sqrt2
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Hope my ans helps you✌️✊
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