cos theta √1 - cos^2theta=1
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==> cos θ - √( 1 - cos² θ) = 1
==> cos θ - √sin² θ = 1 ( •°• sin² θ + cos² θ = 1 )
==> cos θ - sin θ = 1
Square both sides:
==> 1 - 2sinθcosθ = 1
==> 2sinθcosθ = 0
So,
θ = 90° or θ = 0°
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