Question

cos theta = 1/root3 then find sin theta and tan theta​

Answer 1

Answer:

let theta be O

cosO = 1/√3

1/secO = 1/√3

secO = √3

sec²O = 3

1+ tan²O = 3

tan²O = 2

tanO =√2

tanO= sinO/cos O

√2 = sinO × √3

sin O = √2/√3