Question

Cos theta=2/3 then find the value of 4+4tan^2 theta

Answer 1

let theta= x
so we have,
cos x= 2/3
sec x= 1/cos x
sec x= 1/(2/3)
sec x= 3/2
now we have to find the value of
4+4tan²x
=4(1+tan²x)
=4(sec²x)...................... as, [ sec²A-tan²A=1]
........................................therefore sec²A= 1+tan²A
=4(sec x)²
=4(3/2)²
=4×9/4
=9

Answer 2

Answer:

9 is the answer

Step-by-step explanation:

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