Question

cos theta-2cos^2 theta/2sin^2-sin theta = cot theta





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Answer 1

Answer:

Step-by-step explanation:

Ans in pic

Answer 2

Answer:

(cos@ - 2cos³@)/(2sin³@-sin@)

= cos@(1-2cos²@)/(sin@(2sin²@-1))

= cot@(cos2@)/(cos2@

= cot@