Math, asked by sanjanakaneder, 2 months ago

cos theta × 2cos^3÷2sin^3 theat - sin theta = cot theta

Answers

Answered by arbgamer001

1

Answer:

2cos

3

θ−cosθ

sinθ−2sin

3

θ

=

cosθ(2cos

2

θ−1)

sinθ(1−2sin

2

θ)

=

cosθ.cos2θ

sinθ.cosθ

=

cosθ

sinθ

=tanθ.

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