Question

cos theta=3/5 find sec²theta+1/sec²theta-1​

Answer 1

Answer:

cosθ=

2

1

∵cos60

∘

=

2

1

∴θ=60

∘

then sec60

∘

=2

tan60

∘

=

3

∴

1+tan

2

60

∘

2sec60

∘

=

1+(

3

)

2

2×2

⇒

1+3

4

=

4

4

=1

Answer 2

Given::

cos theta =3/5

To find::

$\frac{ { \sec }^{2} \theta + 1}{ { \sec }^{2} \theta - 1}$

➟1/cos theta =sec theta

sec theta=5/3

$\frac{ \sec {}^{2} \theta + 1}{\sec {}^{2} \theta - 1} = \frac{ (\frac{ {5} }{3}) ^{2} + 1}{(\frac{ {5} }{3}) ^{2} - 1}$

$= > \frac{ \frac{25}{9} + 1 }{ \frac{25}{9} - 1} = \frac{25 + 9}{25 - 9} = \frac{34}{16}$

=>17/8