cos theta = 35/37 then find the value of sin theta
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Answer:
cos theeta=35/37
we know,
sin^2theeta +cos^2 theeta=1
=> sin^2 theeta=1-cos^2 theeta=1-(35 /37)^2
=> sin^2 theeta={(37)^2-(35)^2}/(37)^2
=> sin^2theeta =(37+35)(37-35)/(37)^2
=> sin^2 theeta=72×2/(37)^2
=> sin^2theeta=(12)^2/(37)^2
=> sin theeta=12/37
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