Math, asked by varsharajmane333, 3 months ago

cos theta = 35/37 then find the value of sin theta​

Answers

Answered by bagkakali
7

Answer:

cos theeta=35/37

we know,

sin^2theeta +cos^2 theeta=1

=> sin^2 theeta=1-cos^2 theeta=1-(35 /37)^2

=> sin^2 theeta={(37)^2-(35)^2}/(37)^2

=> sin^2theeta =(37+35)(37-35)/(37)^2

=> sin^2 theeta=72×2/(37)^2

=> sin^2theeta=(12)^2/(37)^2

=> sin theeta=12/37

Answered by dbthakkar231979
2

Step-by-step explanation:

I hope it helpful for you completely

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