Question

cos theta=8\17 that sin2theta=kaya hoga

Answer 1

34/16 = 17/6

Hence sin theta = 1/cos = 17/6

Answer 2

hey !!!

cos ¢ = 8/17 = b/h , -------1)

consider that a triangle in which b is base p is perpendicular and h is heighpotenious ...

now , by using Pythagoras theorem ..

p =√h²- b²

p = √17²-8²

p = √289-64..

p = √225 =15


sinA = p/h =15/17 ------2)

now ,, as we know that

sin2A= 2sinA ×cosA

sin2A = 2 × 15×8/17×17 { from 1 and 2 }

sin2A = 240/289 = 0.830444 Answer ...

hope it helps !!

#Rajukumar111