Math, asked by ananya2902, 10 months ago

Cos theta by 1+sin theta =tan (π/4-theta/2

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Answered by paulerdo
0

the answer is explained in the image.

hope it will help you.

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Answered by sandy1816
0

 \frac{cos \theta}{ 1 + sin \theta}  \\  \\  =  \frac{sin( \frac{\pi}{2}  -  \theta)}{1 + cos( \frac{\pi}{2} -  \theta) }  \\  \\  =  \frac{2sin \frac{ \frac{\pi}{2} -  \theta }{2} cos \frac{ \frac{\pi}{2}  -  \theta}{2} }{2 {cos}^{2} \frac{ \frac{\pi}{2} -  \theta }{2}  }  \\  \\  =  \frac{sin( \frac{\pi}{4} -  \frac{ \theta}{2}  )}{cos( \frac{\pi}{2}  -   \frac{ \theta}{2}) }  \\  \\  = tan( \frac{\pi}{2}  -  \frac{ \theta}{2} )

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