(cos theta by sin 90 degree minus theta) + (cos 90 degree - theta by sin 90 degree - theta) - 3 tan square 30 degree
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Let, theta=x
then,
cos x/sin(90-x) +cos(90-x)/sin(90-x)-3tan^2 30°
=cos x/cos x+sin x/cos x-3×(1/root 3)^2
=1+tan x -3×1/3
=1+tan x -1
=tan x
=tan theta
then,
cos x/sin(90-x) +cos(90-x)/sin(90-x)-3tan^2 30°
=cos x/cos x+sin x/cos x-3×(1/root 3)^2
=1+tan x -3×1/3
=1+tan x -1
=tan x
=tan theta
Lucky20031:
hey see....there is a small mistake....1+tan theta - 3×1/3=1+ tan theta -1 = tan theta
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here is ur answer
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