Question

Cos theta / cosec theta + 1 + cos theta / cosec theta - 1 = 2 tan theta

Answer 1

This might help you with your problem

Answer 2

Answer:

Step-by-step explanation:

LHS=$\frac{cos{\theta}}{cosec{\theta}+1}+\frac{cos{\theta}}{cosec{\theta}-1}$

=$\frac{cos{\theta}cosec{\theta}-cos{\theta}+cos{\theta}cosec{\theta}+cos{\theta}}{coec^{2}{\theta}-1}$

=$\frac{cos{\theta}cosec{\theta+cos{\theta}cosec{\theta}}}{cosec^{2}{\theta}-1}$

=$\frac{2cos{\theta}cosec{\theta}}{1-\frac{sin^{2}{\theta}}{sin^{2}{\theta}}}$

=$\frac{2cos{\theta}cosec{\theta}sin^{2}{\theta}}{cos^{2}{\theta}}$

=$2tan{\theta}$

=RHS