Question

cos theta + cot theta /1-sin^2 theta​

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{cos \theta + cot \theta}{1 - {sin}^{2} \theta} \\ \\ = \frac{cos \theta(1 + cosec \theta)}{ {cos}^{2} \theta} \\ \\ = \frac{1 + cosec \theta}{cos \theta} \\ \\ = sec \theta + sec \theta cosec \theta$