cos theta equal to 3 by 2
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cos theta = b/h ,therefore b=3 and h=2
then find p
therefore, 2^2=p^2+3^2
4=p^2+6
p^2=6-4
p=2
h=2
b=3
then find p
therefore, 2^2=p^2+3^2
4=p^2+6
p^2=6-4
p=2
h=2
b=3
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