cos theta + iota sin theta whole power 4 / sin theta + iota cos theta equals to cos 8 theta + iota sin theta
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Answer:
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Step-by-step explanation:
Correct option is
C
sin9θ−icos9θ
(sinθ+icosθ)
5
(cosθ+isinθ)
4
=
i
5
(cosθ−isinθ)
5
(cosθ+isinθ)
4
[∵i
2
=−1)
=
i(cosθ−isinθ)
5
(cosθ+isinθ)
4
=−i(cosθ+isinθ)
4
×(
cosθ−isinθ
1
)
5
=−i(cosθ+isinθ)
4
×(cosθ+isinθ)
5
(∵
cosθ+isinθ
1
=cosθ−isinθ)
=−i(cosθ+isinθ)
9
=−i(cos9θ+isin9θ) (∵(cosθ+isinθ)
m
=cosmθ+isinmθ)
=−icos9θ+sin9θ
∴
(sinθ+icosθ)
5
(cosθ+isinθ)
4
=sin9θ−icos9
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