Question

cos theta minus cos 60+theta minus cos 60 minus theta

Answer 1

Answer:

Step-by-step explanation:

=Cos@-Cos(60°+@)-Cos(60°-@)

=Cos@- [2Cos60°Cos@]

=Cos@-2×1/2Cos@

=Cos@- Cos@

=0

Answer 2

HLW MATE!
Your Solution is given Below:
:cos theta-cos(60+theta)-cos(60-theta)
:cos theta-(cos60cos theta-sin60sin theta)-(cos60cos theta+sin60sin theta)
:cos theta-cos60cos theta+sin60sin theta-cos60cos theta-sin60sin theta
:cos theta-2cos60cos theta (as sin60sin theta is cancelled)
THEN, taking cos theta common
:cos theta(1-2cos 60) [putting value of cos60=1/2 ]
:cos theta×(1-1)
cos theta×0=0
HENCE answer is a)=0
THANK U☺