cos theta = n cos (theta + pi) prove ( n+1)tan(theta+pi)=(n-1)cot pi
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Step-by-step explanation:
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tan(πcosθ)=tan(2π−πsinθ)
⇒πcosθ=nπ+2π−πsinθ(n∈I)
⇒π(sinθ+cosθ)=(2n+1)2π
⇒sinθ+cosθ=22n+1
⇒cos(4π−θ)=222n+1
Since −1≤cos(4π−θ)≤1
⇒−1≤222n+1≤1
⇒n=0,−1 as n is an integer
⇒cos(4π−θ)=±(221)
⇒8cos2(π/4−θ)=1
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