cos theta + sec theta is equal to K then what is the value of sin square theta minus tan square theta
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Steps:
let theta = x
cosx + secx=k
on squaring both sides
cos^2x+sec^2x+2cosxsecx=k^2
As, cosx = 1/sec
so,
cos^2x+sec^2x+2=k^2_____(1)
As we know,
1-sin^2x=cos^2x___(2)
and
1+tan^2x=sec^2x___(3)
so from equation 1,2 and 3
1-sin^2x + 1+tan^2x + 2 = k^2
=> -sin^2x + tan^2x = k^2 - 4
by multiplying minus on both sides
sin^2x - tan^2x = 4 - k^2
Answer:
4 - k^2
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