Cos theta / ( sec theta + tan theta) = 1 + sin theta
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Step-by-step explanation:
cosA/secA+tanA
cosA / 1/cosA+sinA/cosA
cosA × 1+sinA /cosA
1+sinA
Anonymous:
yes my mistake
sorry
and check
right hand side
it's not 1+sinA
1-sinA
bcoz .. cos^2A /1+sinA
cos^2A
1 - sin square A
=(1-sinA)(1+sinA)
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