Question

(Cos theta-(Sin 90-theta) (Cos theta + Sin (90-theha

Answer 1

Answer:

0

Explanation:

Here I am using A instead of theta.

[cosA-sin(90-A)][cosA+sin(90-A)]

= [cosA - cosA][ cosA+cosA]

= 0 × ( 2cosA )

= 0

••••

Answer 2

= (cosA-(sin90_A) (CosA +sin(90-A))

=(CosA - cosA) (cosA +cosA)

= 0 (2cosA)

=0

There fore, the answer is 0